The Scattering of α and β Particles by Matter and the Structure of the Atom - PDF

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E. Rutherford, Philos. Mag, 6, The Scattering of α and β Particles by Matter and the Structure of the Atom E. Rutherford University of Manchester 1 (Received April 1911) 1 It is well known that

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E. Rutherford, Philos. Mag, 6, The Scattering of α and β Particles by Matter and the Structure of the Atom E. Rutherford University of Manchester 1 (Received April 1911) 1 It is well known that the α and β particles suffer deflexions from their rectilinear paths by encounters with atoms of matter. This scattering is far more marked for the β than for the α particle on account of the much smaller momentum and energy of the former particle. There seems to be no doubt that such swiftly moving particles pass through the atoms in their path, and that the deflexions observed are due to the strong electric field traversed within the atomic system. It has generally been supposed that the scattering of a pencil of α or β rays in passing through a thin plate of matter is the result of a multitude of small scattering by the atoms of matter traversed. The observations, however, of Geiger and Marsden 2 on the scattering of α rays indicate that some of the α particles must suffer a deflexions of more than a right angle at a single encounter. They found, for example, that a small fraction of the incident α particles, about 1 in 20,000 turned through an average angle of 90 degrees in passing through a layer of gold foil about cm. thick, which was equivalent in stopping power of the α particle to 1.6 millimetres of air. Geiger 3 showed later that the most 1 Communicated by the author. A brief account of this paper was communicated to the Manchester Literary and Philosophical Society in February, Proc. Roy. Soc., LXXXII, p. 495 (1909) 3 Proc. Roy. Soc. LXXXIII. p (1910). 1 probable angle of deflexions for a pencil of α particles traversing a gold foil of this thickness was about A simple calculation based on the theory of probability shows that the chance of an α particle being deflected through 90 degrees is vanishingly small. In addition, it will be seen later that the distribution of the α particles for various angles of large deflexion does not follow the probability law to be expected if such deflexions are made up of a large number of small deviations. It seems reasonable to suppose that the deflexion through a large angle is due to a single atomic encounter, for the chance of a second encounter of a kind to produce a large deflexion must in most cases be exceedingly small. A simple calculation shows that the atom must be a seat of an intense electric field in order to produce such a large deflexion at a single encounter. Recently Sir J.J. Thomson 4 has put forward a theory to explain the scattering of electrified in passing through small thickness of matter. The atom is supposed to consist of a number N of negatively charged corpuscles, accompanied by an equal quantity of positive electricity uniformly distributed throughout a sphere. The deflexion of a negatively electrified particle in passing through the atom is ascribed to two causes (1) the repulsion of the corpuscles distribution through the atom, and (2) the attraction of the positive electricity in the atom. The deflexion of the particle in passing through the atom is supposed to be small, while the average deflexion after a large number m of encounters was taken as m θ, where θ is the average deflexion due to a single atom. It was shown that the number N of the electrons within the atom could be deduced from observations of the scattering of electrified particles. The accuracy of this theory of compound scattering was examined experimentally by Crowther 5 in a later paper. His result apparently confirmed the main conclusions of the theory, and he deduced, on the assumption that the positive electricity was continuous, that the number of electrons in an atom was about three times its atomic weight. The theory of Sir J.J. Thomson is based on the assumption that the scattering due to a single encounter is small, and the particular structure assumed for the atom does not admit of a very large deflexion of an α particle in traversing a single unless it be supposed that the diameter of the sphere of positive electricity is minute compared with the diameter of the sphere of influence of the atom. Since the α and β particles traverse the atom, it should be possible 4 Camb. Lit. & Phil. Soc. XV. pt. 5 (1910). 5 Crowther, Proc. Roy. Soc. LXXXIV. p.226 (1910). 2 from a close study of the nature of the deflexion to form some idea of the constitution of the atom to produce the effects observed. In fact, the scattering of high speed charged particles by the atoms of matter is one of the most promising methods of attack of this problem. The development of the scintillation method of counting single α particles affords unusual advantages of investigation, and the researches of H. Geiger by this method have already added much to our knowledge of the scattering of α rays by matter. 2 We shall first examine theoretically the single encounters 6 with an atom of simple structure, which is able to produce large deflexions of an α particle, and then compare the deductions from the theory with the experimental data available. Consider an atom which contains a charge ± Ne at its centre surrounded by a sphere of electrification containing a charge N e supposed uniformly distributed throughout a sphere of radius is the fundamental unit of charge, which in this paper is taken as E.S. unit. We shall suppose that for distances less than cm. the central charge and also the charge on the α particle may be supposed to be concentrated at a point. It will be shown that the main deductions from the theory are independent of whether the central charge is supposed to be positive or negative. For convenience, the sign will be assumed to be positive. The question of the stability of the atom proposed need not be considered at this stage, for this will obviously depend upon the minute structure of the atom, and on the motion of the constituent charged parts. In order to from some idea of the forces required to deflect an α particle through a large angle, consider an atom containing a positive charge Ne at its centre, and surrounded by a distribution of negative electricity N e uniformly distributed within a sphere of radius R. The electric force X and the potential V at a distance r from the centre of an atom for a point inside the atom, are given by ( 1 X = Ne r 2 r ) R 3 6 The deviation of a particle throughout a considerable angle from an encounter with a single atom will in this paper be called single scattering. The deviation of a particle resulting from a multitude of small deviations will be termed compound scattering 3 V = Ne ( 1 r 3 ) 2R + r2 2R 3 Suppose an α particle of mass m velocity u and charge E shot directly towards the centre of the atom. It will be brought to rest at a distance b from the centre given by 1/2mu 2 = NeE ( 1 b 3 2R + ) b2 2R 3. It will be seen that b is an important quantity in later calculations. Assuming that the central charge is 100e. it can be calculated that the value of b for an α particle of velocity cms. per second is about cm. In this calculation b is supposed to be very small compared with R. Since R is supposed to be of the order of the radius of the atom, viz cm., it is obvious that the α particle before being turned back penetrates so close to the central charge, that the field due to the uniform distribution of negative electricity may be neglected. In general, a simple calculation shows that for all deflexions greater than a degree, we may without sensible error suppose the deflexion due to the field of the central charge alone. Possible single deviations due to the negative electricity, if distributed in the form of corpuscles, are not taken into account at this stage of the theory. It will be shown later that its effect is in general small compared with that due to the central field. Consider the passage of a positive electrified particle close to the centre of an atom. Supposing that the velocity of the particle is not appreciably charged by its passage through the atom, the path of the particle under the influence of a repulsive force varying inversely as the square of the distance will be an hyperbola with the centre of the atom S as the external focus. Suppose the particle to enter the atom in the direction P O [Fig. 44 1], and that the direction on motion on escaping the atom is OP. OP and OP make equal angles with the line SA, where A is the apse of the hyperbola. p = SN = perpendicular distance from centre on direction of initial motion of particle. Let angle P OA = θ. Let V = velocity of particle on entering the atom, ν its velocity at A, then from consideration of angular momentum. From conservation of energy pv = SA v 1/2mV 2 = 1/2mv 2 + NeE SA, 4 v 2 = V 2 (1 b SA ) Рис. 1: Since the eccentricity is see θ SA = SO + OA = p cosecθ(1 + cos θ) = p cot θ/2 p 2 = SA(SA b) = p cot θ/2(p cot θ/2 b), b = 2p cot θ. The angle of deviation φ of the particle is π 2θ and cot φ/2 = 2p 7 (1) b This gives the angle of deviation of the particle in terms of b, and the perpendicular distance of the direction of projection from the centre of the atom. For illustration, the angle of deviation φ for different values of p/b are shown in the following table: p/b φ 3 Probability of Single Deflexion Through any Angle Suppose a pencil of electrified particles to fall normally on a thin screen of matter of thickness t. With the exception of the few particles which are scattered through a large angle, the particles are supposed to pass nearly normally through the plate with only a small change of velocity. Let n = number of atom in unit volume of material. Then the number of collisions of the particle with the atom of radius R is πr 2 nt in the thickness t. The probability m of entering an atom within a distance p of its centre is given by m = πp 2 nt. Chance dm of striking within radii p and p + dp is given by since dm = 2πp n t dp = π 4 ntb2 cot φ/cosec 2 φ/2dφ (2) cot φ/2 = 2p/b. The value of dm gives the fraction of the total number of particles which are deviated between the angles φ and φ + dφ. The fraction ρ of the total number of particles which are deflected through an angle greater than φ is given by ρ = π 4 ntb2 cot 2 φ/2 (3) by The fraction ρ which is deflected between the angles φ 1 and φ 2 is given ρ = π 4 ntb2 (cot 2 φ 1 2 cot2 φ 2 2 ) (4) It is convenient to express the equation (2) in another from for comparison with experiment. In the case of the α rays, the number of scintillation appearing on a constant area of a zinc sulphide screen are counted for different angles with the direction of incidence of the particles. Let r = distance from point of incidence of α rays on scattering material, then if Q be the total number of particles falling on the scattering material, the 6 number y of α particles falling on until area which are deflected through an angle φ is given by y = Qdm 2πr 2 sin φ dφ = ntb2 Q cosec 4 φ/2 16r 2 (5) Since b = 2NeE mu 2, we see from this equation that a number of α particles (scintillations) per unit area of zinc sulphide screen at a given distance r from the point of incidence of the rays is proportional to (1) cosec 4 φ/2 or 1/φ 4 if φ be small; (2) thickness of scattering material t provided this is small; (3) magnitude of central charge Ne; (4) and is inversely proportional to (mu 2 ) 2, or to the fourth power of velocity if m be constant. In these calculations, it is assumed that the α particles scattered through a large angle suffer only large deflexion. For this to hold, it is essential that the thickness of the scattering material should be so small that the chance of a second encounter involving another large deflexion is very small. If, for example, the probability of a single deflexion φ in passing through a thickness t is 1/1000, the probability, of two successive deflexions each of value φ is 1/10 6, and is negligibly small. The angular distribution of the α particles scattered from a thin metal sheet affords one the simplest methods of testing the general correctness of this theory of single scattering. This has been done recently for α rays by Dr. Geiger, 8 who found that the distribution for particles deflected between 30 degrees and 150 degrees from a thin gold foil was substantial agreement with the theory. A more detailed account of these and other experiments to test the validity of the theory will be published later. 8 Manch. Lit. & Phil. Soc 4 Alteration of Velocity in an Atomic Encounter It has so far been assumed that an α or β particles does not suffer an appreciable change of velocity as the result of a single atomic encounter resulting in large deflexion of the particle. The effect of such an encounter in altering the velocity of the particle can be calculated on certain assumptions. It is supposed that only two systems are involved, viz., the swiftly moving particle and the atom which it traverses supposed initially at rest. It is supposed that the principle of conservation of momentum and of energy applies and that there is no appreciable loss of energy or momentum by radiation. Let m be mass of the particle ν 1 = velocity of approach, ν 2 = velocity of recession, M = mass of atom, V = velocity communicated to atom as result of encounter. Let OA [Fig. 44 2] represent in magnitude and direction the momentum mv 1 of the entering particle, and OB the momentum of the receding particle which has been turned through an angle AOB = φ. Then BA represents in magnitude and direction the momentum M V of the recoiling atom. (MV ) 2 = (mv 1 ) 2 + (mv 2 ) 2 2m2v 1 v 2 cos φ. (1) By the conservation of energy MV 2 = mv 2 1 mv 2 2 (2) Suppose M/m = K and v 2 = ρv 1, where ρ is 1. From (1) and (2), (K + 1)ρ 2 2ρ cos φ = K 1, or ρ = cos φ K K + 1 K 2 sin 2 φ. Consider the case of an α particle of atomic weight 4, deflected through an angle of 90 degrees by an encounter with an atom of gold of atomic weight Рис. 2: Since K = 49 nearly, ρ = K 1 K + 1 =.979, or the velocity of the particle is reduced only about 2 per cent. by the encounter. In the case of aluminium K = 27/4 and for φ = 90, ρ =.86, It is seen that the reduction of velocity of the α particle becomes marked on this theory for encounters with the lighter atoms. since the range of an α particle in air or other matter is approximately proportional to the cube of the velocity, it follows that an α particle of range 7 cms. has its range reduced to 4.5 cms. after incurring a single deviation of 90 degrees in traversing an aluminium atom. This is of magnitude to be easily detected experimentally. Since the value of k is very large for an encounter of a β particle with an atom, the reduction of velocity on this formula is very small. Some very interesting cases of the theory arise in considering the changes of velocity and the distribution of scattered particles when the α particle encounters a light atom, for example a hydrogen or helium atom. A discussion of these and similar cases is reserved until the question has been examined experimentally. 9 5 Comparison of single and compound scattering Before comparing the results of theory with experiment, it is desirable to consider the relative importance of single and compound scattering in determining the distribution of the scattering particles. Since the atom is supposed to consist of a central charge surrounded by a uniform distribution of the opposite sign through a sphere of radius R, the chance of encounters with the atom involving small deflexions is very great compared with the chance of a single large deflexion. This question of compound scattering has been examined by Sir J.J. Thomson in the paper previously discussed ( 1). In the notation of this paper, the average deflexion φ 1 due to the field of the sphere of positive electricity of radius R and quantity Ne was found by him to be φ 1 = π 4 NeE mu 2 1 R. The average deflexion φ 2 due to the N negative corpuscles supposed distributed uniformly throughout the sphere was found to be φ 2 = 16eE 5mu 2 1 R 3N 2. The mean deflexion due to both positive and negative electricity was taken as (φ φ 2 2) 1/2. In a similar way, it is not difficult to calculate the average deflexion due to the atom with a central charge discussed in this paper. Since the radial electric field X at any distance r from the centre is given by ( 1 X = Ne r 2 r ) R 3, it is not difficult to show that the deflexion (supposed small) of an electrified particle due to this field is given by θ = b p ( ) 3/2 1 p2 R 2, where p is the perpendicular from the centre on the path of the particle and b has the same value as before. It is seen that the value of θ increases with diminution of p and becomes great for small values of φ. 10 Since we have already seen that the deflexions become very large for a particle passing near the centre of the atom, it is obviously not correct to find the average values by assuming θ is small. Taking R of the order 10 8 cm, the value of p for a large deflexion is for α and β particles of the order cm. Since the chance of an encounter involving a large deflexion is small compared with the chance of small deflexions, a simple consideration shows that the average small deflexion is practically unaltered if the large deflexions are omitted. This is equivalent to integrating over that part of the cross section of the atom where the deflexions are small and neglecting the small central area. It can in this way be simply shown that the average small deflexion is given by φ 1 = 3π 8 b R. This value of φ 1 for the atom a concentrated central charge is three times the magnitude of the average deflexion for the same value of Ne in the type of atom examined by Sir J.J. Thomson. Combining the deflexions due to the electric field and to the corpuscles, the average deflexion is (φ φ 2 2) 1/2 or ( b 2R ) 1/2. N It will be seen later that the value of N is nearly proportional to the atomic weight, and is about 100 for gold. The effect due to scattering of the individual corpuscles expressed by the second term of the equation is consequently small for heavy atoms compared with that due to the distributed electric field. Neglecting the second term, the average deflexion per atom is 3πb/8R. We are now in a position to consider the relative effects on the distribution of particles due to single and to compound scattering. Following J.J. Thomson s argument, the average deflecion θ t after passing through a thickness t of matter is proportional to the square of the number of encounters and is given by θ t = 3πb 8R πr 2 nt = 3πb 8 πnt, where n as before is equal to the number of atoms per unit volume. The probability p 1 for compound scattering that the deflexion of the particle is greater than φ is equal e φ/θ2 t. Consequently φ 2 = 9π3 64 b2 nt log p 1. 11 Next suppose that single scattering alone is operative. We have seen ( 3) that the probability p 2 of deflexion greater than φ is given by By comparing these two equations φ is sufficiently small that p 2 = π 4 b2 n tcot 2 φ/2. p 2 log p 1 = 0.181φ 2 ctg 2 φ/2, tan φ/2 = φ/2, p 2 log p 1 = If we suppose p = 0.5, than p 1 = If p 2 = 0.1, p 1 = It is evident from this comparison, that the probability for any given deflexion is always greater for single than for compound scattering. The difference is especially marked when only a small fraction of the particles are scattered through any given angle. It follows from this result that the distribution of particles due to encounters with the atoms is for small thickness mainly governed by single scattering. No doubt compound scattering produces some effect in equalizing the distribution of the scattered particles; but its effect becomes relatively smaller, the smaller the fraction of the particles scattered through a given angle. 6 Comparison of Theory with Experiments On the present theory, the value of the central charge Ne is an important constant
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