1 Zadaci Lentoviden Temel

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Lentoviden temel

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  Lentovidni temeli od armiran beton   Zada~a 1.   Da se presmeta lentoviden temel od armiran beton pod armirano-betonsko platno so debelina od 40 cm  koe na gornata povr{inata na temelot prenesuva optovaruvawe prika`ano na skicata. 1)  Opredeluvawe na {irinata na temelot. m2,401,10250,85190 400 doz =⋅⋅−=β−= γσ  f b DPB   usvoeno: B   =  2,40 m  ; m1,020,402,402 o =−=−=  bBb   2)  Opredeluvawe na visinata na temelot. kPa125,02,40300 ,  === BPp  ggn   kPa41,6672,40100 ,  === BPp  ppn   kPa275,041,6671,81251,61,81,6 ,,  =⋅+⋅=+=  pngnn  ppp   0,541,6671,80,51251,6 21,821,6 2,2, 11  ⋅⋅+⋅⋅=+= − bpbpM pngnu   mkNm/137,5 11 ′= − u M   1,041,6671,81,01251,61,81,6 ,, 11  ⋅⋅+⋅⋅=⋅+⋅= −  bpbpQ pngnu   mkN/275,0 11 ′= − u Q   Za usvoeno MB 20 , ε a   =  10‰  i ε b   =  2‰  se dobiva: k z   =  0,937  ; k h   =   2,619 Visinata opredelena so pomo{ na momentite kako stati~ki golemini e: 27    Glava 1.  LENTOVIDEN TEMEL, TEMEL POD YID cm30,711,0137,52,619 11 ===  − bMkh  uh M   h t   =  30,71 +  5,0 =  35,71 cm Visinata opredelena so pomo{ na transverzalnite sili iznesuva: cm36,70m0,367 1,08000,937275,0 11 ==⋅⋅=⋅τ⋅=  − str zu bkQh Q   h t   =  36,70 +  5,0 =  41,70 cm usvoeno: h t   =  45,0 cm 3)  Konstruktivni karakteristiki. 4)  Kontrola na napregawa. G T    =   V ⋅ γ b V   =   V 1   +   V 2   =  0,45 ⋅ 2,40 +  0,40 ⋅ 0,65 =  1,34 m 3 G T    =  1,34 ⋅ 25,0 =  33,5 kN/m ′   G P   = (2,40 ⋅ 1,10 −  1,34) ⋅ 19,0 =  24,7 kN/m ′   G   =   G T    +   G P   =  33,5 +  24,7 =  58,2 kN/m ′  kPa190,922,4058,2400 max  =+=+= BGPp   %5)(3%0,48100 190190,92190100 dozmaxdoz ÷<=⋅ −=⋅−= σσΔ  p   5)  Opredeluvawe na potrebna armatura. 2 cm9,174040,00,93713750 11 =⋅⋅=⋅⋅= σ − vstzup hkM A   28    Lentovidni temeli od armiran beton   usvoeno: 10 ∅ 12 so    A   =  11,3 cm 2  ; RA 400/500 ∅ 8/25 cm  ‡ razdelna armatura  6)  Kontrola od probivawe na a.b. platno niz temelot. astnstpr  hphbP τγτ  ≤+−= 1 322)2( o   kPa87,5400,2275,00,40)2(0,40400 =⋅⋅⋅+− = τ pr    0,50,28251001004011,3 <=⋅⋅==  Σ μ st h A   ⇒   μ  =  0,5   1,1950,51,31,31,31,3 1  =⋅=⋅=  μγ   MPa0,4780,61,195 3232 1  =⋅= τγ  a   MPa0,47808750,  <= τ pr    ⇒   ne e potrebna dopolnitelna kosa armatura. 29    Glava 1.  LENTOVIDEN TEMEL, TEMEL POD YID Zada~a 2.  Da se presmeta temel pod yid so debelina od 25 cm  koj na gornata povr{ina na temelot prenesuva optovaruvawe kako na skicata. 1)  Opredeluvawe na {irinata na temelot. ( σ doz   −   β γ b D f  ) B 2   −   P ⋅ B   −  6 M   =  0 P   =   P g   +   P p   =  140 +  80 =  220 kN/m ′  M   =   H p ⋅ D f    +   M p   =  20 ⋅ 1,2 +  20 =  44 kNm/m ′  (170 −  0,85 ⋅ 25 ⋅ 1,2) B 2   −  220 B   −  6 ⋅ 44 =  0   144,5 B 2   −  220 B   −  264 =  0 ⇒   B   =  2,312 m  usvoeno: B   =  2,35 m   ‡ dol`ina na konzola ............ m1,0520,252,352 o =−=−=  bBb  ‡ {irina na jadro na presek ... m0,3916762,356 ===  Bk  ‡ ekscentricitet ................... m0,1572,351,2250,85220 44 =⋅⋅⋅+ =+= GPMe   e   <   k   ⇒  simetri~en temel so mal ekscentricitet  2)  Opredeluvawe na visinata na temelot. kPa59,5742,35140 ,  === BPp  ggn   47,8034,0432,354462,35806 22,  ±=⋅±=±= BMBPp  pppn   [kPa]13,75781,843 , ⎩⎨⎧−= pn p   30  
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